No where does it say that $merge == Object.merge In fact, if you look in the compat script, it's obvious they are meant to be different.
On Tue, Oct 12, 2010 at 2:46 PM, Perrin Perrin <[email protected]>wrote: > From 1.2 docs: > > var obj1 = {a: 0, b: 1}; > var obj2 = {c: 2, d: 3}; > var obj3 = {a: 4, d: 5}; > var merged = $merge(obj1, obj2, obj3); //returns {a: 4, b: 1, c: 2, d: 5}, > (obj1, obj2, and obj3 are unaltered) > > > > var nestedObj1 = {a: {b: 1, c: 1}}; > var nestedObj2 = {a: {b: 2}}; > var nested = $merge(nestedObj1, nestedObj2); //returns: {a: {b: 2, c: 1}} > > > > On Tue, Oct 12, 2010 at 4:44 PM, Ryan Florence <[email protected]>wrote: > >> From the 1.3 docs: >> >> var obj1 = {a: 0, b: 1}; >> var obj2 = {c: 2, d: 3}; >> var obj3 = {a: 4, d: 5}; >> var merged = Object.merge(obj1, obj2, obj3); // returns {a: 4, b: 1, c: 2, >> d: 5}, (obj2, and obj3 are unaltered) >> >> merged === obj1; // true, obj1 gets altered and returned as merged object >> >> var nestedObj1 = {a: {b: 1, c: 1}}; >> var nestedObj2 = {a: {b: 2}}; >> var nested = Object.merge(nestedObj1, nestedObj2); // returns: {a: {b: 2, c: >> 1}} >> >> >> >> On Oct 12, 2010, at 3:39 PM, Oskar Krawczyk wrote: >> >> Ouch. >> >> Yes, this should not happen. >> >> Can you post a ticket on lighthouse? >> >> On 2010-10-12, at 23:32, atom wrote: >> >> bit of unexpected behavior (which might be intentional). When using >> >> Object.merge the objects I pass in are being altered, unlike how >> >> $merge used to behave. >> >> >> old way: >> >> >> var obj1 = {a: 1, b: 2, c: 3} >> >> var obj2 = {d: 4, e: 5, f: 6} >> >> var merged = $merge(obj1, obj2); >> >> console.log(obj1); // returns {a: 1, b: 2, c: 3} >> >> >> new way: >> >> >> var obj1 = {a: 1, b: 2, c: 3} >> >> var obj2 = {d: 4, e: 5, f: 6} >> >> var merged = Object.merge(obj1, obj2); >> >> console.log(obj1); // returns {a: 1, b: 2, c: 3, d: 4, e: 5, f: 6} >> >> >> >> >
