In article <a7lmrm$[EMAIL PROTECTED]>, Bamm Gabriana wrote: > It is. > > Let a = 1. > a^2 = a (multiply both sides by a) > a^2 - 1 = a - 1 (subtract 1 from both sides) > (a + 1)(a - 1) = (a - 1) (factor it)
ok. > (a + 1) = 1 (cancel common factors) whoops... a-1 is 0, so you've just divided both sides of your equation by zero! that doesn't leave you with (a+1)=1... > QED/ :) i'm afraid not :) -- michael
