Bamm Gabriana wrote: > It is. > > Let a = 1. > a^2 = a (multiply both sides by a) > a^2 - 1 = a - 1 (subtract 1 from both sides) > (a + 1)(a - 1) = (a - 1) (factor it) > (a + 1) = 1 (cancel common factors) > 1 + 1 = 1 (substitution.) > > QED/ :)
1 + 2 = 3. Ergo 4 + 5 = 6. /Jonas
