Simon Montagu wrote: > Prove that (a + b) (a - b) = a^2 - b^2 > a * a = a^2 > + * - = - > b * b = b^2
Given: x not equal to 0, y not equal to 0, Prove: x + y = 0. Since x does not equal 0, then x + 1 does not equal 1, x + a does not equal a, x + y does not equal y. But what is y? y is anything but 0. Thus x + y is not equal to anything but 0. Since x + y cannot equal anything but 0, x + y = 0. Q.E.D.
