Hi Michael :)
Great, works like a charm.
I reduced it to:
MATCH (:User {id: "456"})-[:PARTICIPATES]->(meeting:Meeting {id: "123"}), (
user)-[:PARTICIPATES]->(meeting)
RETURN user
Thanks a lot,
Michael
On Friday, June 6, 2014 1:42:29 PM UTC+2, Michael Hunger wrote:
>
> MATCH (:User {id: "456"})-[:PARTICIPATES]->(meeting:Meeting {id: "123"})
> MATCH (user)-[:PARTICIPATES]->(meeting)
> RETURN user
>
> Sent from mobile device
>
> Am 06.06.2014 um 13:25 schrieb Michael Azerhad <[email protected]
> <javascript:>>:
>
> MATCH (user)-[:PARTICIPATES]->(meeting:Meeting {id: "123"})
> RETURN user
>
> This query returns all users participating to the Meeting `123`.
>
> Now I want to return all users participating to the Meeting `123` *ONLY
> if user `456` participates in it*.
>
> So concretely, if user1, user2 and user3 participates to the Meeting
> `123`, I don't want to return them.
>
> However if user1, *user456* and user3 participates, I want to return all
> of them (since `456` exists).
>
>
> How could I achieve this query?
> I thought about `WHERE` mixed with `ANY` but didn't succeed.
>
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