That's more expensive then you should see it profile

Sent from mobile device

Am 06.06.2014 um 17:32 schrieb Michael Azerhad <[email protected]>:

> 456 was well returned. 
> However, I change the query to specify the condition in a where clause : 
> MATCH (user)-[:PARTICIPATES]->(meeting:Meeting {id: "123"})
> WHERE {:User {id: "456"}}-[:PARTICIPATES]->(meeting) 
> RETURN user
> 
> Leading to the same result as yours 
> Le 6 juin 2014 à 16:15, Michael Hunger <[email protected]> a 
> écrit :
> 
>> But then 456 is not returned, or?
>> 
>> Sent from mobile device
>> 
>> Am 06.06.2014 um 14:42 schrieb Michael Azerhad <[email protected]>:
>> 
>>> Hi Michael :)
>>> 
>>> Great, works like a charm.
>>> 
>>> I reduced it to: 
>>> 
>>> MATCH (:User {id: "456"})-[:PARTICIPATES]->(meeting:Meeting {id: "123"}), 
>>> (user)-[:PARTICIPATES]->(meeting)
>>> RETURN user
>>> 
>>> Thanks a lot,
>>> 
>>> Michael
>>> 
>>> On Friday, June 6, 2014 1:42:29 PM UTC+2, Michael Hunger wrote:
>>>> 
>>>> MATCH (:User {id: "456"})-[:PARTICIPATES]->(meeting:Meeting {id: "123"})
>>>> MATCH (user)-[:PARTICIPATES]->(meeting)
>>>> RETURN user
>>>> 
>>>> Sent from mobile device
>>>> 
>>>> Am 06.06.2014 um 13:25 schrieb Michael Azerhad <[email protected]>:
>>>> 
>>>>> MATCH (user)-[:PARTICIPATES]->(meeting:Meeting {id: "123"})
>>>>> RETURN user
>>>>> 
>>>>> This query returns all users participating to the Meeting `123`.
>>>>> 
>>>>> Now I want to return all users participating to the Meeting `123` ONLY if 
>>>>> user `456` participates in it.
>>>>> 
>>>>> So concretely, if user1, user2 and user3 participates to the Meeting 
>>>>> `123`, I don't want to return them.
>>>>> 
>>>>> However if  user1, user456 and user3 participates, I want to return all 
>>>>> of them (since `456` exists).
>>>>> 
>>>>> 
>>>>> How could I achieve this query? 
>>>>> I thought about `WHERE` mixed with `ANY` but didn't succeed.
>>>>> 
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