But then 456 is not returned, or?

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Am 06.06.2014 um 14:42 schrieb Michael Azerhad <[email protected]>:

> Hi Michael :)
> 
> Great, works like a charm.
> 
> I reduced it to: 
> 
> MATCH (:User {id: "456"})-[:PARTICIPATES]->(meeting:Meeting {id: "123"}), 
> (user)-[:PARTICIPATES]->(meeting)
> RETURN user
> 
> Thanks a lot,
> 
> Michael
> 
> On Friday, June 6, 2014 1:42:29 PM UTC+2, Michael Hunger wrote:
>> 
>> MATCH (:User {id: "456"})-[:PARTICIPATES]->(meeting:Meeting {id: "123"})
>> MATCH (user)-[:PARTICIPATES]->(meeting)
>> RETURN user
>> 
>> Sent from mobile device
>> 
>> Am 06.06.2014 um 13:25 schrieb Michael Azerhad <[email protected]>:
>> 
>>> MATCH (user)-[:PARTICIPATES]->(meeting:Meeting {id: "123"})
>>> RETURN user
>>> 
>>> This query returns all users participating to the Meeting `123`.
>>> 
>>> Now I want to return all users participating to the Meeting `123` ONLY if 
>>> user `456` participates in it.
>>> 
>>> So concretely, if user1, user2 and user3 participates to the Meeting `123`, 
>>> I don't want to return them.
>>> 
>>> However if  user1, user456 and user3 participates, I want to return all of 
>>> them (since `456` exists).
>>> 
>>> 
>>> How could I achieve this query? 
>>> I thought about `WHERE` mixed with `ANY` but didn't succeed.
>>> 
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