> Power each tube's filament in parallel from the 5v supply, in series with a > voltage dropping resistor. Since the filament will draw a fixed amount of > current, one can easily calculate the value of the resistor needed to lower > the 5v supply to the supply voltage appropriate for the filament. This has > the disadvantage of wasting a lot of power in the resistor, however.
It also has the advantage to soft-starting the filaments - cold filaments have low resistance and draw heavier current until they warm up. The series resistors limit this current surge. - John -- You received this message because you are subscribed to the Google Groups "neonixie-l" group. To post to this group, send an email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/neonixie-l?hl=en-GB.
