If you want to make this rock-solid, the pulldown resistor can be 
calculated knowing the  max tristate leakage current (usually 10uA) and 
ensuring that 10uA of leakage does not produce enough base-current to turn 
on the transistor.

Worst-case, you will have a transistor with infinite current-gain (beta). 
Then the problem is to prevent voltage at the base to start turning on 
(0.7V). That works out to 70K. This is approximate, because there is 
additional leakage current at the transistor itself (collector-base 
leakage), which is typically much less than 1uA.  This is just a 
quick-and-dirty calculation and in a real circuit the pulldown resistor 
will have a  higher value; if you factor-in transistor beta (lets pick 100) 
and take a swag at how much current is required before the nixie starts to 
glow (my experiments with b7971 tubes show 100-150uA is needed), an emitter 
resistor of about 1.5K, the pulldown resistor works out to 94K, which is 
pretty close to the quick-and-dirty value.

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