Yeah I saw that afterward. That's very cool. But I'm still on 6.0 so I have to wait :\
cheers, Michael 2011/3/23 chris <[email protected]> > hmm, not sure if this is any use, but i've just seen the > release notes for 6.2v3 which mention: > > • BUG ID 16729 - Python: A format() function was added to > nuke.Node class to enable querying for the format that a > particular node uses. > > ++ chris > > > > > On 3/22/11 at 5:12 PM, [email protected] (Michael Havart) wrote: > > Hi Ron, >> >> just trying to match the width and height of the node with the width and >> height of one of the formats: >> >> def getFormat(node): >> w,h = int(node.width()), int(node.height()) >> >> for format in nuke.formats(): >> if w == format.width() and h == format.height(): >> print node.name()+' has this format: '+format.name() >> >> getFormat(nuke.selectedNode()) >> >> Michael >> >> >> >> 2011/3/22 Ron Ganbar <[email protected]> >> >> Hmmm... >>> OK, anyone: is there a way to call up in an expression the >>> >> current format >> >>> of a node? Not the height and width, but the whole format? >>> >> > _______________________________________________ > Nuke-users mailing list > [email protected] > http://support.thefoundry.co.uk/cgi-bin/mailman/listinfo/nuke-users >
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