How about the Z depth from the scanline renderer? Seems that if you calculate an object position, it would only be the transform pivot, unless you use something like depth?
R On Sep 18, 2013 1:39 PM, "Frederich Munch" <[email protected]> wrote: > The aforementioned node actually does the opposite, removing any baked in > transforms and is a part of the Dynamics set. > > That said you could pipe the geometry into a DyPassive body, then into a > DySolver and bake the solver. It will create a group, inside will be an > axis with the world-space matrix keyframed. You could cut-paste that axis > and delete the passive body and solver. > > Or you could try to bake out the transform with only Nuke, but I've never > had much success in automating it (due to the viewer update issues) > nuke.toNode( <> ).knob('geo_select').getGeometry()[ <object index> > ].transform().translation() > > > > ------------------------------ > CC: [email protected] > From: [email protected] > Subject: Re: [Nuke-users] distance between camera and transformed object > Date: Wed, 18 Sep 2013 07:22:28 +0100 > To: [email protected] > > can't remember which node but Mr Munch (?) geometry tools has a tool that > can read the concatenated position of an object. > > apologies if his name is wrong but he mentioned this in a similar ish > thread a while ago. > > > Howard > > On 18 Sep 2013, at 02:45, Michael Garrett <[email protected]> wrote: > > Normally I would say you can use the world_matrix knob of the TransformGeo > to get the concatenated position (using cels 3, 7 and 11) but it depends on > whether the geometry itself already has a baked in offset or not - meaning > is it reading in at the origin or not. > > If it's not animated and you need that offset value in world space, you > could easily snap an Axis to a vertex of the geometry that you want to be > the Camera focal point, then parent another Axis that represents the > TransformGeo and read off the concatenated transform from the child Axis > world_matrix knob. You would then use the expression Olivier posted to get > the distance. > > > On 17 September 2013 19:41, Gustaf Nilsson <[email protected]> wrote: > > Yes, but that is not possible when you have a transformgeo-node connected > to the geometry as there is no way (?) of getting its world coordinates. > > > On Tue, Sep 17, 2013 at 6:56 PM, Olivier Lavenant < > [email protected]> wrote: > > You can use the expression : sqrt[(Xa-Xb)²+(Ya-Yb)²+(Za-Zb)²] > > > 2013/9/17 Gustaf Nilsson <[email protected]> > > heya > > Is it possible to get the distance between the camera and an object in 3d > space that has an arbitrary number of transforms below it? > > Thanks > > -- > ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ > > _______________________________________________ > Nuke-users mailing list > [email protected], http://forums.thefoundry.co.uk/ > http://support.thefoundry.co.uk/cgi-bin/mailman/listinfo/nuke-users > > > > _______________________________________________ > Nuke-users mailing list > [email protected], http://forums.thefoundry.co.uk/ > http://support.thefoundry.co.uk/cgi-bin/mailman/listinfo/nuke-users > > > > > -- > ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ > > _______________________________________________ > Nuke-users mailing list > [email protected], http://forums.thefoundry.co.uk/ > http://support.thefoundry.co.uk/cgi-bin/mailman/listinfo/nuke-users > > > _______________________________________________ > Nuke-users mailing list > [email protected], http://forums.thefoundry.co.uk/ > http://support.thefoundry.co.uk/cgi-bin/mailman/listinfo/nuke-users > > > _______________________________________________ Nuke-users mailing list > [email protected], http://forums.thefoundry.co.uk/ > http://support.thefoundry.co.uk/cgi-bin/mailman/listinfo/nuke-users > > _______________________________________________ > Nuke-users mailing list > [email protected], http://forums.thefoundry.co.uk/ > http://support.thefoundry.co.uk/cgi-bin/mailman/listinfo/nuke-users >
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