On Wed, Jul 9, 2008 at 6:39 PM, Gabriel Dos Reis wrote:
> On Wed, Jul 9, 2008 at 3:38 PM, Bill Page <[EMAIL PROTECTED]> wrote:
>>>>>
>>>>>> *yixin.cao wrote:* -- In the light of polynomial, (2d) is a
>>>>>> non-zero polynomial, so that it's always safe to write (1/(2d))
>>>>>>
>>>> ...
>>
>>> On Wed, Jul 9, 2008 at 10:38 AM, Bill Page wrote:
>>>> But is computing in the field Q(d) "safe" if we eventually intend to
>>>> replace d with some non-symbolic value?
>>>
>>
>> On Wed, Jul 9, 2008 at 3:56 PM, Gabriel Dos Reis wrote:
>>> That is a question separate from whether the polynomial 2*d is
>>> nonzero or not.  There is no doubt it is nonzero.
>>>
>>
>> Call it whatever you like.
>
> Then that is unfortunate, because it seems the solution presented
> is being dismissed for another proposal, when in fact the other
> proposal refuses to be careful in its terminology and semantics.
>

I do not recall any solution being presented. I did not intend to
dismiss anything.

>> My question is: "Is yixin.cao's original claim true?"
>
> His claim was that the polynomial 2d is nonzero

The part of his claim that interests me is this:

"  ...  so that it's always safe to write (1/(2d))"

>  -- again, I stress for the casual reader that `d' is the unknown.
> That such a simple claim could be seen as untrue escapes my
> understanding.
>

'd' is unknown so it can take any value - including zero, right?

> ...
> That you need to be careful in your arguments.
>

I was only asking a question.

>>
>> How will 'Symbolic T' deal with this issue?
>>  How will it be different from Polynomial?
>
> Symbolic T is not a Polynomial T, therefore does not use
> simplification rules from the field of quotients of Polynomial T.
>

Ok.

Regards,
Bill Page.

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