Re: SQL Query

[Mike Spalinger]

Imran,

Tom Kyte has a thread that might help:
http://asktom.oracle.com/pls/ask/f?p=4950:8:1554835115460038644::NO::F4950_P8_DISPLAYID,F4950_P8_CRITERIA:229614022562,
Essentially, you can do this:

CREATE or replace FUNCTION CONCAT_LIST( cur SYS_REFCURSOR )
  RETURN  VARCHAR2 IS
    ret VARCHAR2(32000);
    tmp VARCHAR2(4000);
BEGIN
    loop
        fetch cur into tmp;
        exit when cur%NOTFOUND;
            ret := ret || ' ' || tmp;
    end loop;
    RETURN ret;
END;
/
SQL> select * from mike;

        ID TEXT             ORDR
---------- ---------- ----------
         1 B                   2
         1 A                   1
         1 C                   3
SELECT id, SUBSTR(CONCAT_LIST(CURSOR(
   SELECT text
      FROM (select id, text, ordr from mike order by ordr) ee
      WHERE e.id = ee.id)),1,40) list
FROM ( select distinct id from mike) e;
        ID LIST
---------- --------------------
         1  A B C
Mike

Imran Ashraf wrote:
Hi,

I have the following data , table Temp

ID  Text   Order
1     B        2
1     A        1
1     C        3
I want to write a query which says: wherever there is more than 1 occurrence
of ID then  concatenate the text in the order specified in the order column.
So i would get:
ID  Text
1     A B C
Any suggestions?

Thanks

Imran


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