Mike,
Just wanted to supplement your example with another one from my
environment (uses nested tables with CAST and MULTISET to achieve the
same):
SELECT c.customer_id
,customer_name
,utils.code_table_to_string(CAST( MULTISET(
SELECT distinct dlr_dealer_code
FROM dealer_customers dc
,dlr_dealer_master_t
WHERE dc.customer_id = dc_in.customer_id
AND dlr_dealer_id = dc.dealer_id
ORDER BY dlr_dealer_code
) AS code_table_t
)) spans_these_dealers
FROM customers c
,(
SELECT customer_id
FROM dealer_customers
GROUP BY customer_id
HAVING COUNT(distinct dealer_id) > 1
) dc_in
WHERE dc_in.customer_id = c.customer_id;
Does eseentially the same thing. In this case it concatenates the
dealer_codes per customer (identifies customers spanning multiple
dealers) on the same row. Here is a sample of the output:
2969473096 Mountain Enterprises Inc D100,D470,D480
2969473121 K C Construction B010,B150,B190
2969473195 GOODFELLOW BROS H140,H330
The TYPE code_table_t is defined as:
TYPE CODE_TABLE_T IS table of varchar2(3000);
And the conversion function is very similar in its functionality to
dbms_utility.comma_to_table procedure:
FUNCTION code_table_to_string (in_table code_table_t, in_rec_sep
varchar2 DEFAULT config.c_rec_sep)
RETURN delimited_list_t
IS
v_list delimited_list_t;
BEGIN
FOR i IN 1..in_table.COUNT
LOOP
IF i = 1
THEN
v_list := in_table(1);
ELSE
v_list := v_list||in_rec_sep||in_table(i);
END IF;
END LOOP;
RETURN v_list;
END code_table_to_string;
As opposed your suggestion of using the following:
SELECT id, CONCAT_LIST(CURSOR(
> SELECT text
> FROM mike m_in
ORDER BY ordr
> WHERE m_in.id = m.id)) list
> FROM ( select distinct id from mike) m;
--- Mike Spalinger <[EMAIL PROTECTED]> wrote:
> Imran,
>
> Tom Kyte has a thread that might help:
>
http://asktom.oracle.com/pls/ask/f?p=4950:8:1554835115460038644::NO::F4950_P8_DISPLAYID,F4950_P8_CRITERIA:229614022562,
>
> Essentially, you can do this:
>
> CREATE or replace FUNCTION CONCAT_LIST( cur SYS_REFCURSOR )
> RETURN VARCHAR2 IS
> ret VARCHAR2(32000);
> tmp VARCHAR2(4000);
> BEGIN
> loop
> fetch cur into tmp;
> exit when cur%NOTFOUND;
> ret := ret || ' ' || tmp;
> end loop;
> RETURN ret;
> END;
> /
>
> SQL> select * from mike;
>
> ID TEXT ORDR
> ---------- ---------- ----------
> 1 B 2
> 1 A 1
> 1 C 3
>
> SELECT id, SUBSTR(CONCAT_LIST(CURSOR(
> SELECT text
> FROM (select id, text, ordr from mike order by ordr) ee
> WHERE e.id = ee.id)),1,40) list
> FROM ( select distinct id from mike) e;
>
> ID LIST
> ---------- --------------------
> 1 A B C
>
> Mike
>
>
> Imran Ashraf wrote:
> > Hi,
> >
> > I have the following data , table Temp
> >
> > ID Text Order
> > 1 B 2
> > 1 A 1
> > 1 C 3
> >
> >
> > I want to write a query which says: wherever there is more than 1
> occurrence
> > of ID then concatenate the text in the order specified in the
> order column.
> > So i would get:
> >
> > ID Text
> > 1 A B C
> >
> > Any suggestions?
> >
> > Thanks
> >
> > Imran
>
>
> --
> Please see the official ORACLE-L FAQ: http://www.orafaq.net
> --
> Author: Mike Spalinger
> INET: [EMAIL PROTECTED]
>
> Fat City Network Services -- 858-538-5051 http://www.fatcity.com
> San Diego, California -- Mailing list and web hosting
> services
>
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=====
Sundeep Maini
Consultant
Currently on Assignement at Caterpillar Peoria
[EMAIL PROTECTED]
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