Note that, obviously, one of Decimal's claims to fame is that it
considers trailing zeros as significant, so serializing /should/
record those details.
If you want to adjust that, use Decimal.Round(value, 2), but note that
this does not add trailing zeros, only removes extras.
--
Regards,
Mark Hurd, B.Sc.(Ma.)(Hons.)
On 11 August 2013 14:32, Corneliu I. Tusnea <corne...@acorns.com.au> wrote:
> Hi,
>
> Anyone working today?
>
> How can I force the NewtonSoft Json Serializer to serialize two decimals the
> same way? decimal a = 1234.1200M; decimal b = 1234.12M;
>
> var sa = JsonConvert.SerializeObject(new { value = a });
> var sb = JsonConvert.SerializeObject(new {value = b});
> Console.WriteLine(sa);
> Console.WriteLine(sb);
>
> Results are: {"value":1234.1200} {"value":1234.12}
>
> How can I force it to serialize them both with 4 decimals so the results are
> identical?
>
> Even simpler, ignoring the serializer, how can I make sa.ToString() ==
> sb.ToString() ?
> The Json Serializer is only doing a simple .ToString() behind the scenes.
>
> Regards,
> Corneliu
>
