Hi Corneliu,
I based my thoughts on my assumption that the WriteValue(decimal) method,
would need to output a string representation of the decimal value. The
documentation (
http://james.newtonking.com/projects/json/help/index.html?topic=html/Methods_T_Newtonsoft_Json_JsonTextWriter.htm)
does not help at all here. Looking at where you call the base
WriteValue(decimal) method I would have thought that you could call
WriteValue(string)?
So:
public override void WriteValue(decimal value)
{
// we really really really want the value to be serialized as
"0.0000" not "0.00" or "0.0000"!
value = Math.Round(value, 4);
// divide first to force the appearance of 4 decimals
value = Math.Round((((value+0.00001M)/10000)*10000)-0.00001M, 4);
base.WriteValue(value);
}
Would become:
public override void WriteValue(decimal value)
{
string result = value.ToString("0.0000");
base.WriteValue(result);
}
WARNING: This solution is NOT tested!
Regards
Greg H
On Mon, Aug 12, 2013 at 9:03 AM, Corneliu I. Tusnea
<corne...@acorns.com.au>wrote:
> Greg,
>
> That still does not make it easy to use with the JSON serializer where my
> main issue is.
> Here is an solution I found to work reliably across any value I throw at
> it.
> private class JsonTextWriterOptimized : JsonTextWriter
> {
> public JsonTextWriterOptimized(TextWriter textWriter)
> : base(textWriter)
> {
> }
> public override void WriteValue(decimal value)
> {
> // we really really really want the value to be serialized as
> "0.0000" not "0.00" or "0.0000"!
> value = Math.Round(value, 4);
> // divide first to force the appearance of 4 decimals
> value = Math.Round((((value+0.00001M)/10000)*10000)-0.00001M, 4);
> base.WriteValue(value);
> }
> }
>
> Then use the custom writer:
>
> var jsonSerializer = Newtonsoft.Json.JsonSerializer.Create();
> var sb = new StringBuilder(256);
> var sw = new StringWriter(sb, CultureInfo.InvariantCulture);
> using (var jsonWriter = new JsonTextWriterOptimized(sw))
> {
> jsonWriter.Formatting = Formatting.None;
> jsonSerializer.Serialize(jsonWriter, instance);
> }
>
>
>
>
>
>
> On Mon, Aug 12, 2013 at 1:38 AM, Greg Harris <harris.gre...@gmail.com>wrote:
>
>> I would have thought that
>> ? ((decimal)123.45).ToString("0.0000")
>> "123.4500"
>> would be cheaper faster more understandable?
>>
>> On Sun, Aug 11, 2013 at 6:57 PM, Corneliu I. Tusnea <
>> corne...@acorns.com.au> wrote:
>>
>>> Yes, that's my issue. It seems that if you somehow tell is there are
>>> multiple zeros is keeps than and displays them during the .ToString().
>>> This is what I ended up doing:
>>> private class JsonTextWriterOptimized : JsonTextWriter
>>> {
>>> public JsonTextWriterOptimized(TextWriter textWriter)
>>> : base(textWriter)
>>> {
>>> }
>>>
>>> public override void WriteValue(decimal value)
>>> {
>>> // we really really really want the value to be serialized as
>>> "0.0000" not "0.00" or "0.0000"!
>>> //This is very important for all our hash calculations
>>> *value = Math.Round(value, 4); *
>>> * value = Math.Round((((value+0.00001M)/10000)*10000)-0.00001M, 4); //
>>> divide first to force the appearance of 4 decimals*
>>> base.WriteValue(value);
>>> }
>>> }
>>> The I use this writer during the serialization.
>>>
>>> That will make 123.12 > 123.1200 and even 100 to 100.0000 :)
>>>
>>>
>>>
>>> On Sun, Aug 11, 2013 at 5:34 PM, Mark Hurd <markeh...@gmail.com> wrote:
>>>
>>>> Note that, obviously, one of Decimal's claims to fame is that it
>>>> considers trailing zeros as significant, so serializing /should/
>>>> record those details.
>>>>
>>>> If you want to adjust that, use Decimal.Round(value, 2), but note that
>>>> this does not add trailing zeros, only removes extras.
>>>>
>>>> --
>>>> Regards,
>>>> Mark Hurd, B.Sc.(Ma.)(Hons.)
>>>>
>>>>
>>>> On 11 August 2013 14:32, Corneliu I. Tusnea <corne...@acorns.com.au>
>>>> wrote:
>>>> > Hi,
>>>> >
>>>> > Anyone working today?
>>>> >
>>>> > How can I force the NewtonSoft Json Serializer to serialize two
>>>> decimals the
>>>> > same way? decimal a = 1234.1200M; decimal b = 1234.12M;
>>>> >
>>>> > var sa = JsonConvert.SerializeObject(new { value = a });
>>>> > var sb = JsonConvert.SerializeObject(new {value = b});
>>>> > Console.WriteLine(sa);
>>>> > Console.WriteLine(sb);
>>>> >
>>>> > Results are: {"value":1234.1200} {"value":1234.12}
>>>> >
>>>> > How can I force it to serialize them both with 4 decimals so the
>>>> results are
>>>> > identical?
>>>> >
>>>> > Even simpler, ignoring the serializer, how can I make sa.ToString() ==
>>>> > sb.ToString() ?
>>>> > The Json Serializer is only doing a simple .ToString() behind the
>>>> scenes.
>>>> >
>>>> > Regards,
>>>> > Corneliu
>>>> >
>>>>
>>>
>>>
>>
>
