Yes, that's my issue. It seems that if you somehow tell is there are
multiple zeros is keeps than and displays them during the .ToString().
This is what I ended up doing:
private class JsonTextWriterOptimized : JsonTextWriter
{
public JsonTextWriterOptimized(TextWriter textWriter)
: base(textWriter)
{
}
public override void WriteValue(decimal value)
{
// we really really really want the value to be serialized as
"0.0000" not "0.00" or "0.0000"!
//This is very important for all our hash calculations
*value = Math.Round(value, 4); *
* value = Math.Round((((value+0.00001M)/10000)*10000)-0.00001M, 4); //
divide first to force the appearance of 4 decimals*
base.WriteValue(value);
}
}
The I use this writer during the serialization.
That will make 123.12 > 123.1200 and even 100 to 100.0000 :)
On Sun, Aug 11, 2013 at 5:34 PM, Mark Hurd <markeh...@gmail.com> wrote:
> Note that, obviously, one of Decimal's claims to fame is that it
> considers trailing zeros as significant, so serializing /should/
> record those details.
>
> If you want to adjust that, use Decimal.Round(value, 2), but note that
> this does not add trailing zeros, only removes extras.
>
> --
> Regards,
> Mark Hurd, B.Sc.(Ma.)(Hons.)
>
>
> On 11 August 2013 14:32, Corneliu I. Tusnea <corne...@acorns.com.au>
> wrote:
> > Hi,
> >
> > Anyone working today?
> >
> > How can I force the NewtonSoft Json Serializer to serialize two decimals
> the
> > same way? decimal a = 1234.1200M; decimal b = 1234.12M;
> >
> > var sa = JsonConvert.SerializeObject(new { value = a });
> > var sb = JsonConvert.SerializeObject(new {value = b});
> > Console.WriteLine(sa);
> > Console.WriteLine(sb);
> >
> > Results are: {"value":1234.1200} {"value":1234.12}
> >
> > How can I force it to serialize them both with 4 decimals so the results
> are
> > identical?
> >
> > Even simpler, ignoring the serializer, how can I make sa.ToString() ==
> > sb.ToString() ?
> > The Json Serializer is only doing a simple .ToString() behind the scenes.
> >
> > Regards,
> > Corneliu
> >
>
