On Wed, Mar 26, 2008 at 12:16 PM, Luc Le Blanc <[EMAIL PROTECTED]> wrote: > According to C operator precedence, &(a->b) is equivalent to &a->b and the > same goes for &(a.b) But recently, I recall fixing a bug by adding > parentheses, or am I right? To be sure, how can I view the generated ASM code > under CW 9.3?
Right click on the file in the project and choose "Disassemble" to see the generated code. -- For information on using the ACCESS Developer Forums, or to unsubscribe, please see http://www.access-company.com/developers/forums/
