Ben Combee wrote: > On Wed, Mar 26, 2008 at 12:16 PM, Luc Le Blanc <[EMAIL PROTECTED]> > wrote: > > According to C operator precedence, &(a->b) is equivalent to > > &a->b and the same goes for &(a.b) But recently, I recall fixing > > a bug by adding parentheses, or am I right? To be sure, how can > > I view the generated ASM code under CW 9.3?
> Right click on the file in the project and choose "Disassemble" > to see the generated code. Thanks. It works fine, and indeed, both expressions generate the same code. My impression was wrong. Luc Le Blanc -- For information on using the ACCESS Developer Forums, or to unsubscribe, please see http://www.access-company.com/developers/forums/
