cool guys, but i was asking for an average "sum" object :) 2015-12-08 9:19 GMT-02:00 Christof Ressi <[email protected]>:
> Hey Matt, > > there's no need for the feedback path (and therefore no [block~ 1] ;-)) > > Just use the following formula: > > y[n] = (y[n-1] - x[n-k])/k > > where k is the number of samples to be averaged (must be at least 1). see > the patch I sent to Alex in my last mail. > it uses [rpole~ 1] for the y[n-1] part and [z~ k] for the x[n-k] part (you > can replace the latter one with a [delwrite~] [delread~] pair to make it > purely vanilla). > > The funny thing about linear moving average filters is, that although it > can be implemented as a recursive filter (like in both our patches), it is > still a FIR filter (and therefore it defeats the notion that recursive > filters are always IIR filters). The impulse response is just a rectangular > pulse and therefore finite. > > > > Gesendet: Dienstag, 08. Dezember 2015 um 07:13 Uhr > Von: "Matt Barber" <[email protected]> > An: "Alexandre Torres Porres" <[email protected]> > Cc: "[email protected]" <[email protected]> > Betreff: Re: [PD] Moving Sum object? > > Something like this? Almost completely untestsed. :D > > On Tue, Dec 8, 2015 at 12:20 AM, Alexandre Torres Porres <[email protected]> > wrote: > > Talking about averages I wonder if we have an object that sums (in a > moving average fashion) a series of samples > > cheers > _______________________________________________ > [email protected][[email protected]] mailing list > UNSUBSCRIBE and account-management -> > http://lists.puredata.info/listinfo/pd-list[http://lists.puredata.info/listinfo/pd-list] > _______________________________________________ [email protected] > mailing list UNSUBSCRIBE and account-management -> > http://lists.puredata.info/listinfo/pd-list[http://lists.puredata.info/listinfo/pd-list] >
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