what was the purpose of the output from the max object into rpole~ in your patch? that's a bug, right?
cheers 2015-12-08 9:50 GMT-02:00 Christof Ressi <[email protected]>: > Or are you talking about a object that outputs the sum as a message? In > that case just use [cmavg~] or [maverage~] with [snapshot~]. If you just > want the sum of a signal vector, there are some objects in zexy that will > do the job, like [avg~] or [pack~]+[sum] > > *Gesendet:* Dienstag, 08. Dezember 2015 um 12:41 Uhr > *Von:* "Christof Ressi" <[email protected]> > > *An:* "Alexandre Torres Porres" <[email protected]> > *Cc:* "[email protected]" <[email protected]> > *Betreff:* Re: [PD] Moving Sum object? > Well, a linear moving average filter is just something that sums a > series of samples. If you don't want the average but rather the true sum, > either multiply the output by the number of samples or take my abstraction > and get rid of the [/~] object. > > *Gesendet:* Dienstag, 08. Dezember 2015 um 12:21 Uhr > *Von:* "Alexandre Torres Porres" <[email protected]> > *An:* "Christof Ressi" <[email protected]> > *Cc:* "Matt Barber" <[email protected]>, "[email protected]" < > [email protected]> > *Betreff:* Re: Re: [PD] Moving Sum object? > cool guys, but i was asking for an average "sum" object :) > > 2015-12-08 9:19 GMT-02:00 Christof Ressi <[email protected]>: >> >> Hey Matt, >> >> there's no need for the feedback path (and therefore no [block~ 1] ;-)) >> >> Just use the following formula: >> >> y[n] = (y[n-1] - x[n-k])/k >> >> where k is the number of samples to be averaged (must be at least 1). see >> the patch I sent to Alex in my last mail. >> it uses [rpole~ 1] for the y[n-1] part and [z~ k] for the x[n-k] part >> (you can replace the latter one with a [delwrite~] [delread~] pair to make >> it purely vanilla). >> >> The funny thing about linear moving average filters is, that although it >> can be implemented as a recursive filter (like in both our patches), it is >> still a FIR filter (and therefore it defeats the notion that recursive >> filters are always IIR filters). The impulse response is just a rectangular >> pulse and therefore finite. >> >> >> >> Gesendet: Dienstag, 08. Dezember 2015 um 07:13 Uhr >> Von: "Matt Barber" <[email protected]> >> An: "Alexandre Torres Porres" <[email protected]> >> Cc: "[email protected]" <[email protected]> >> Betreff: Re: [PD] Moving Sum object? >> >> Something like this? Almost completely untestsed. :D >> >> On Tue, Dec 8, 2015 at 12:20 AM, Alexandre Torres Porres < >> [email protected]> wrote: >> >> Talking about averages I wonder if we have an object that sums (in a >> moving average fashion) a series of samples >> >> cheers >> _______________________________________________ >> [email protected][[email protected]] mailing list >> UNSUBSCRIBE and account-management -> >> http://lists.puredata.info/listinfo/pd-list[http://lists.puredata.info/listinfo/pd-list] >> _______________________________________________ [email protected] >> mailing list UNSUBSCRIBE and account-management -> >> http://lists.puredata.info/listinfo/pd-list[http://lists.puredata.info/listinfo/pd-list] > > _______________________________________________ [email protected] > mailing list UNSUBSCRIBE and account-management -> > http://lists.puredata.info/listinfo/pd-list >
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