here's a better patch

2015-12-08 15:44 GMT-02:00 Alexandre Torres Porres <[email protected]>:

> I've made it work with this design in fexpr, but it's only good up to half
> the block size
>
>
> 2015-12-08 15:21 GMT-02:00 Alexandre Torres Porres <[email protected]>:
>
>> As I say in the attached patch; problem is that whenever you change the
>> number of samples without clearing or clearing the filter, it goes crazy...
>>
>> not sure how to fix this.
>>
>> cheers
>>
>>
>> 2015-12-08 10:40 GMT-02:00 Christof Ressi <[email protected]>:
>>
>>> the filter is working perfectly well for me. send me your testing patch.
>>>
>>>
>>>
>>> Gesendet: Dienstag, 08. Dezember 2015 um 13:36 Uhr
>>> Von: "Alexandre Torres Porres" <[email protected]>
>>> An: "Christof Ressi" <[email protected]>
>>> Cc: "[email protected]" <[email protected]>
>>> Betreff: Re: Re: Re: [PD] Moving Sum object?
>>>
>>> not sure this is working either, I'm getting negative values when
>>> testing it with count~ (only positive values)
>>>
>>> 2015-12-08 10:30 GMT-02:00 Christof Ressi <[email protected]>:It
>>> certainly is and I have no idea how that happened :-D. but it has no effect
>>> whatsoever. just delete the connection.
>>>
>>>
>>> Gesendet: Dienstag, 08. Dezember 2015 um 13:20 Uhr
>>> Von: "Alexandre Torres Porres" <[email protected][[email protected]]>
>>> An: "Christof Ressi" <[email protected][[email protected]]>
>>> Cc: "[email protected][[email protected]]" <[email protected][
>>> [email protected]]>
>>> Betreff: Re: Re: [PD] Moving Sum object?
>>>
>>> what was the purpose of the output from the max object into rpole~ in
>>> your patch? that's a bug, right?
>>>
>>> cheers
>>>
>>> 2015-12-08 9:50 GMT-02:00 Christof Ressi <[email protected][
>>> [email protected]]>:
>>>
>>> Or are you talking about a object that outputs the sum as a message? In
>>> that case just use [cmavg~] or [maverage~] with [snapshot~]. If you just
>>> want the sum of a signal vector, there are some objects in zexy that will
>>> do the job, like [avg~] or [pack~]+[sum]
>>>
>>>
>>> Gesendet: Dienstag, 08. Dezember 2015 um 12:41 Uhr
>>> Von: "Christof Ressi" <[email protected][[email protected]][
>>> [email protected][[email protected]]]>
>>>
>>> An: "Alexandre Torres Porres" <[email protected][[email protected]][
>>> [email protected][[email protected]]]>
>>> Cc: "[email protected][[email protected]][[email protected][
>>> [email protected]]]" <[email protected][[email protected]][
>>> [email protected][[email protected]]]>
>>> Betreff: Re: [PD] Moving Sum object?
>>>
>>> Well, a linear moving average filter is just something that  sums a
>>> series of samples. If you don't want the average but rather the true sum,
>>> either multiply the output by the number of samples or take my abstraction
>>> and get rid of the [/~] object.
>>>
>>>
>>> Gesendet: Dienstag, 08. Dezember 2015 um 12:21 Uhr
>>> Von: "Alexandre Torres Porres" <[email protected][[email protected]][
>>> [email protected][[email protected]]]>
>>> An: "Christof Ressi" <[email protected][[email protected]][
>>> [email protected][[email protected]]]>
>>> Cc: "Matt Barber" <[email protected][[email protected]][
>>> [email protected][[email protected]]]>, "[email protected][
>>> [email protected]][[email protected][[email protected]]]" <
>>> [email protected][[email protected]][[email protected][
>>> [email protected]]]>
>>> Betreff: Re: Re: [PD] Moving Sum object?
>>>
>>> cool guys, but i was asking for an average "sum" object :)
>>>
>>> 2015-12-08 9:19 GMT-02:00 Christof Ressi <[email protected][
>>> [email protected]]>:Hey Matt,
>>>
>>> there's no need for the feedback path (and therefore no [block~ 1] ;-))
>>>
>>> Just use the following formula:
>>>
>>> y[n] = (y[n-1] - x[n-k])/k
>>>
>>> where k is the number of samples to be averaged (must be at least 1).
>>> see the patch I sent to Alex in my last mail.
>>> it uses [rpole~ 1] for the y[n-1] part and [z~ k] for the x[n-k] part
>>> (you can replace the latter one with a [delwrite~] [delread~] pair to make
>>> it purely vanilla).
>>>
>>> The funny thing about linear moving average filters is, that although it
>>> can be implemented as a recursive filter (like in both our patches), it is
>>> still a FIR filter (and therefore it defeats the notion that recursive
>>> filters are always IIR filters). The impulse response is just a rectangular
>>> pulse and therefore finite.
>>>
>>>
>>>
>>> Gesendet: Dienstag, 08. Dezember 2015 um 07:13 Uhr
>>> Von: "Matt Barber" <[email protected][[email protected]]>
>>> An: "Alexandre Torres Porres" <[email protected][[email protected]]>
>>> Cc: "[email protected][[email protected]]" <[email protected][
>>> [email protected]]>
>>> Betreff: Re: [PD] Moving Sum object?
>>>
>>> Something like this? Almost completely untestsed. :D
>>>
>>> On Tue, Dec 8, 2015 at 12:20 AM, Alexandre Torres Porres <
>>> [email protected][[email protected]]> wrote:
>>>
>>> Talking about averages I wonder if we have an object that sums (in a
>>> moving average fashion) a series of samples
>>>
>>> cheers
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>>
>>
>

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