Nope - you still don't understand. This is all done with colours well within the gamut of both sensors.
It's easy enough to come up with numeric examples for any given sensor. A moment's thought should make it obvious that this is the case. You've got a multi-dimensional input space; the intensity of illumination at all frequencies (which we can assume bandwidth-limited to remain well withing the gamut of the device in question). The sensor projects this to a smaller-dimensional output space - one (or three) intensity values. This means that there are many input values which all map to the same output value. But when those different colours strike a sensor with a differently-shaped response curve they will yield different results. > give me the conditions where the two won't be captured. on contend that a > digital capture device exceeds the capability of film and that the loss is > in what film is unable to capture. > > Herb.... > ----- Original Message ----- > From: "John Francis" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Sent: Thursday, December 25, 2003 5:21 PM > Subject: Re: What do you think? > > > > > > You're wrong. You've lost too much information in the original capture. > > > > Given any two sensors with different spectral sensitivities it's always > > possible to come up with a pair of stimulus colours which look identical > > to the first sensor, but which appear different to the second sensor. > > > > There's no way you can post-process that first image to simulate the > > response of the second sensor; you can never distinguish between the > > two colours which produced identical responses on the first sensor. > >
