Jon,lis
Well that was easy! Ha ha ha. I built one screwed up object. I have a bad
habit of taking a number of things and counting them as one. So I took ABC =5
and then proceeded to put successive elements in a dual relation to the
collection (abc).
It makes no sense. Thus.
ABC =5
D (abc) add 1
(abc) D convert = 7
ED (abc) add 1
(abc) ED convert = 9
FED (abc) add 1
(abc) FED convert =11
it makes no apparent sense to "transpose" additional elements with the number
of transpositions in a triple and add them to the number. Maybe you could
build a replica of ABC.....
(fed) (abc) = two identical collections of the number of transpositions in a
triple.
Reduce to
g:g ("11" would need explaining)
In any case, I am beginning to think that ch. 3 follows a methodological
pattern: counting "unlocks" relations, relations "unlock" matrices, and
matrices "unlock" geometry.
Jim W
> Date: Tue, 3 Mar 2015 09:26:33 -0500
> From: [email protected]
> To: [email protected]; [email protected]
> Subject: Re: Peirce's 1880 “Algebra Of Logic” Chapter 3 • Selection 7
>
> Re: Jim Willgoose
> At: http://permalink.gmane.org/gmane.science.philosophy.peirce/15768
>
> Jim,
>
> The number of converses of an n-place relation is just n factorial (n!).
> When he says 5 transpositions for a 3-place relation he is just talking
> about the 5 additional ones besides the one you came in with, yielding
> (n! - 1) for the number of what he calls "transposition-functions" of
> an n-fold relative at the end of CP 3.224.
>
> Regards,
>
> Jon
>
> --
>
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