Andrew Shitov: > If the line of code is not ended with ';' the parser tries first > to assume [..]
Wouldn't that be unambigous? foo = 23 bar = \ 42 ? I think there would be no ambiguities and you only had to add additional syntax for the rare cases instead of the common cases. -- Thomas Wittek http://gedankenkonstrukt.de/ Jabber: [EMAIL PROTECTED]