Hi Douglas,

> From http://perldoc.perl.org/functions/substr.html:
> substr has a 4th argument (or you can use substr as an lvalue) for
> replacement.
> From http://doc.perl6.org/routine/substr I don't see any way to do a
> replacement. What is the idiomatic way of doing a positional string
> replacement in Perl 6? Thanks!

I believe `substr-rw` is what you're looking for:

$ perl6
> my $s = "The black cat climbed the green tree";
The black cat climbed the green tree
> my $z = substr-rw($s, 14, 7) = "jumped from";
> $s.say
The black cat jumped from the green tree

As far as I know, not all of its behaviour has been implemented yet (FWIW it
looks like it shouldn't have returned "jumped" above; my guess is that it
should have been "climbed".  Nevertheless, it seems to do that which you're
looking for.

Hope that helps!



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