On 6/8/2015 4:04 PM, Bruce Gray wrote:
On Jun 8, 2015, at 3:51 PM, Douglas E. Miles <d...@veritablesoftware.com> wrote:
substr has a 4th argument (or you can use substr as an lvalue) for replacement.
From http://doc.perl6.org/routine/substr I don't see any way to do a
replacement. What is the idiomatic way of doing a positional string replacement
in Perl 6? Thanks!
$ perl6 -e 'my $s = "abc"; $s.substr-rw(1,1) = "z"; say $s;'
$ perl6 -e 'my $s = "abc"; substr-rw($s, 1,1) = "z"; say $s;'
I also do not see substr-rw in doc.perl6.org.
It needs to be added.
In the meantime, you can find it here:
Hope this helps,
Bruce Gray (Util of PerlMonks)