Hi All,
I need to read a file into a buffer (NO CONVERSIONS!)
and then convert it to a string (again with no
conversions).
I have been doing this:
for ( @$BinaryFile ) -> $Char { $StrFile ~= chr($Char); }
But it takes a bit of time. What is the fastest way to do this?
I guess there is not a way to create/declare a variable that is
both Buf and Str at the same time? That would mean I did not
have to convert anything. I use to get away with this under
Module 2 all the time.
$ p6 'my $B = Buf.new(0x66, 0x66, 0x77); $B.Str ~= "z";'
Cannot use a Buf as a string, but you called the Str method on it
in block <unit> at -e line 1
$ p6 'my $B = Buf.new(0x66, 0x66, 0x77); Str($B) ~= "z";'
Cannot use a Buf as a string, but you called the Str method on it
in block <unit> at -e line 1
Many thanks,
-T
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