On Sat, Aug 23, 2008 at 9:15 PM, Arnaud Le Blanc <[EMAIL PROTECTED]> wrote: > Hi, > > On Saturday 23 August 2008 20:16:16 Pierre Joye wrote: >> hi, >> >> >> > +# ifndef HAVE_U_INT32_T >> >> > + typedef uint32_t u_int32_t; >> >> > +# endif >> >> > +#endif >> >> >> >> I don't understand this part. If HAVE_U_INT32_T is not defined, you >> >> still use u_int32_t? >> > >> > If HAVE_U_INT32_T is not defined that means that u_int32_t is not defined. >> > So I define u_int32_t it to uint32_t. This makes sense for me. >> >> It defines unint32_t not u_int32_t. The define should be HAVE_UINT32_T >> if what you test is uint32_t. > > This is a typedef, not a #define ;)
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HAVE_U_INT32_T is a define or a /D (or whatever uses other compilers) :-) -- Pierre http://blog.thepimp.net | http://www.libgd.org -- PHP CVS Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
