The code below is my first attempt at a multiple SELECT. Is there a better way?
Advertising
Thanks
Ken Brill
[EMAIL PROTECTED]
--------------------------------------------------------------------------------
function TotalCountSongs($channel) {
// create a temp table to fill
a.. $sql = "CREATE TABLE `templistcount` {TABLE STUFF DELETED};
b.. $result = mysql_query($sql) or die ("\n\nCannot read from database\n" .
mysql_errno(). "\n" . mysql_error());
// get the allable genres from the channels database, these are MP3 ID3v2 genres tags
a.. $sql = "SELECT * FROM channels WHERE channel=\"$channel\"";
b.. $result = mysql_query($sql) or die ("</select>\n\nCannot read from database\n" .
mysql_errno(). "\n" . mysql_error());
c.. $row = mysql_fetch_object ($result);
// At this point $t="Rock, Country, Jazz"
a.. $t=$row->types;
b.. $a=explode(", ", $t);
// Now that I have a list of genres (MP3 ID3 genre tags) in $a, I want to pull all the
// songs that match those 3 genres out of the table 'list' and count them
// and to do this I move them one genre at a time to a temp database and
// then select them all and count that. The table 'list' has several thousand song
titles
// from hundreds of genres
a.. foreach ($a as $Genres) {
a.. $Genres=trim($Genres);
b.. $sql = "INSERT INTO templistcount (number, filename, filesize, seconds,
bitrate, sample, copyright, ID3songtitle, ID3artist, ID3album, year, comment , genre)
SELECT number, filename, filesize, seconds, bitrate, sample, copyright, ID3songtitle,
ID3artist, ID3album, year, comment, genre FROM list WHERE genre=\"$Genres\"";
c.. $result = mysql_query($sql) or die ("</select>\n\nCannot copy from database\n"
. mysql_errno(). "\n" . mysql_error());
b.. }
c.. $sql = "SELECT * FROM templistcount";
d.. $result = mysql_query($sql) or die ("</select>\n\nCannot count items in
database\n" . mysql_errno(). "\n" . mysql_error());
e.. $num_rows = mysql_num_rows($result);
f.. $sql = "DROP TABLE templistcount";
g.. $result = mysql_query($sql) or die ("</select>\n\nCannot count items in
database\n" . mysql_errno(). "\n" . mysql_error());
h.. return $num_rows;
}
