By "last record", do you mean the last was inserted into the database?  If
so, look to MYSQL's auto_increment and last_insert_id().

> -----Original Message-----
> From: DL Neil [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, January 23, 2002 2:08 PM
> To: Zach Curtis
> Cc: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] # of Records in Table
>
>
> Zach,
>
> How can this "last record" be identified? Is there a key field or
something
> similar?
>
> Again: We might need to see the table definition to answer this.
>
> Please advise,
> =dn
>
>
> ----- Original Message -----
> From: "Zach Curtis" <[EMAIL PROTECTED]>
> To: "DL Neil" <[EMAIL PROTECTED]>
> Sent: 23 January 2002 20:49
> Subject: RE: [PHP-DB] # of Records in Table
>
>
> > The last record should be whatever the last record is in the table. For
> > example, if there are 1000 records in the table which COUNT(*) will tell
> me,
> > how can I get the password for record 1000. The only thing I can do that
> > would probably work is two query statements, one selecting COUNT(*) and
> the
> > other selecting "password". What I don't like about this method is that
I
> > would have to retrieve all of the passwords into an array, which I would
> > assume would be slow on larger tables. Ideally, I thought their would be
a
> > way to do this operation in one select statement. Any thoughts?
> >
> >
> > Zach
> >
> > -----Original Message-----
> > From: DL Neil [mailto:[EMAIL PROTECTED]]
> > Sent: Wednesday, January 23, 2002 1:11 PM
> > To: Zach Curtis; [EMAIL PROTECTED]
> > Subject: Re: [PHP-DB] # of Records in Table
> >
> >
> > Zach,
> >
> > > What syntax can I use to determine how many records are in a MySQL
table
> > and
> > > then retrieve the value of the field "password" for the last record? I
> > tried
> > > using some combinations of COUNT(*) and LIMIT with no success.
> >
> >
> > SELECT COUNT(*) will answer the first part. What did you try that lacked
> > success?
> >
> > How do you define "last record"? We might need to see the table
definition
> > to answer this.
> >
> > Regards,
> > =dn
> >
> >
> >
> >
> >
>
>
>
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