You could use this script:
<?php
$columns = 3;
$count = 0;
while ($query_data = $yoursearch){
$count++;
if ($count < $columns)
{
echo "<td>$query_data[]</td>";
}
else if ($count == $columns)
{
$count = 0;
echo "<tr><td>$query_data[]</td>";
}
for ($i=$count;$i<=$columns;$i++){
echo "<td> </td>";
}
echo "</tr>";
}
?>
I think it works.
Bye,
Moreno
-----Messaggio originale-----
Da: Dave Carrera [mailto:[EMAIL PROTECTED]]
Inviato: lunedi 18 febbraio 2002 13.07
A: php List
Oggetto: [PHP-DB] I cant get the logic for this...
Hi all,
I want to display return results from my query (which works fine)
In I tidy way on screen.
So my result returns say seven results, I have a table, and I want to
show
3 results per row of the table... I.e.:
Table
TR
TD = result1 /TD TD result2 /TD TD = result3 /TD
/TD
/TR
TR
TD = result4 /TD TD result5 /TD TD = result6 /TD
/TD
/TR
TR
TD = result7 /TD TD resultempty /TD TD = resultempty /TD
/TD
/TR
/table
The last two td in row 3 are empty because result found 7 results.
This cant be fixed so echo statements wont work as the result could
Be 3 or 10 or 56 or whatever.....
As Always your help and or guidance in this matter is appreciated.
Dave Carrera
Php / MySql Development
Web Design
Site Marketing
http://www.davecarrera.com
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