$today = date("Ymd");
$sql = "INSERT into table (date) values ('$today')";
when the $today variable is inserted into a mysql date column it will fit
just right.
but, if you want to insert it into a timestamp column, you will have to padd
it with 6 zero's
Jim Lucas
www.bend.com
----- Original Message -----
From: "Matthew Crouch" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, March 01, 2002 2:50 PM
Subject: [PHP-DB] easy date format question
> should be simple as pie, of course, but i can't find a straightforward
> syntax example in the documentation. i'm trying to change the PHP date
> format to mysql's.
>
> my code:
> $today = date("YYYYMMDD");
> $sql = "INSERT into table (date) values ('$today')";
> and so on...
>
> is filling the date field with zeros, instead of 2002-02-28
>
>
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