Hello!!
it should be
$today = Date("Y"-"m"-"d");
Dan
On Friday, March 1, 2002, at 04:50 PM, [EMAIL PROTECTED] wrote:
> should be simple as pie, of course, but i can't find a straightforward
> syntax example in the documentation. i'm trying to change the PHP date
> format to mysql's.
>
> my code:
> $today = date("YYYYMMDD");
> $sql = "INSERT into table (date) values ('$today')";
> and so on...
>
> is filling the date field with zeros, instead of 2002-02-28
>
>
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