or :

$sql="INSERT INTO table (date) VALUES (now())";

-----Original Message-----
From: Jim Lucas [php] [mailto:[EMAIL PROTECTED]]
Sent: Saturday, March 02, 2002 2:11 AM
To: [EMAIL PROTECTED]; Matthew Crouch
Subject: Re: [PHP-DB] easy date format question


$today = date("Ymd");
$sql = "INSERT into table (date) values ('$today')";

when the $today variable is inserted into a mysql date column it will
fit
just right.
but, if you want to insert it into a timestamp column, you will have to
padd
it with 6 zero's

Jim Lucas
www.bend.com

----- Original Message -----
From: "Matthew Crouch" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, March 01, 2002 2:50 PM
Subject: [PHP-DB] easy date format question


> should be simple as pie, of course, but i can't find a straightforward
> syntax example in the documentation. i'm trying to change the PHP date
> format to mysql's.
>
> my code:
> $today = date("YYYYMMDD");
> $sql = "INSERT into table (date) values ('$today')";
> and so on...
>
> is filling the date field with zeros, instead of 2002-02-28
>
>
> --
> PHP Database Mailing List (http://www.php.net/)
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>
>


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