or : $sql="INSERT INTO table (date) VALUES (now())";
-----Original Message----- From: Jim Lucas [php] [mailto:[EMAIL PROTECTED]] Sent: Saturday, March 02, 2002 2:11 AM To: [EMAIL PROTECTED]; Matthew Crouch Subject: Re: [PHP-DB] easy date format question $today = date("Ymd"); $sql = "INSERT into table (date) values ('$today')"; when the $today variable is inserted into a mysql date column it will fit just right. but, if you want to insert it into a timestamp column, you will have to padd it with 6 zero's Jim Lucas www.bend.com ----- Original Message ----- From: "Matthew Crouch" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Friday, March 01, 2002 2:50 PM Subject: [PHP-DB] easy date format question > should be simple as pie, of course, but i can't find a straightforward > syntax example in the documentation. i'm trying to change the PHP date > format to mysql's. > > my code: > $today = date("YYYYMMDD"); > $sql = "INSERT into table (date) values ('$today')"; > and so on... > > is filling the date field with zeros, instead of 2002-02-28 > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
