Actually, you want the value of the input to be just "$classroom". That is
because it is within the while loop. Can I ask for a little more
information regarding the structure of the table that you are querying--what
is(are) the primary keys in the table; I am assuming that the "week_no"
field is the primary key. I am sorry for the confusion--the complete code
for outputting the input form follows (minus the appropriate form tags).
###SNIP####
echo "<table>";
while ($row = mysql_fetch_array($result)) {
$week_no = $row['week_no'];
$week_date = $row['week_date'];
$parent_id = $row['parent_id'];
$student_id = $row['student_id'];
$class_id = $row['class_id'];
$classroom = $row['classroom'];
$homework = $row['homework'];
$library = $row['library'];
$fieldtrip = $row['fieldtrip'];
$pta = $row['pta'];
$mast = $row['mast'];
$meetings = $row['meetings'];
$other = $row['other'];
echo <<<EOD
<tr><td align=\"center\">
<input type=\"text\" name=\"log[$week_no][classroom]\"
value=\"$classroom\">
</td></tr>
EOD;
}
echo "</table><";
###SNIP####
> -----Original Message-----
> From: John Hughes, Jomari Works [mailto:[EMAIL PROTECTED]]
> Sent: Monday, March 11, 2002 11:03 PM
> To: Shrock, Court; [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] Creating an array of mySQL results with PHP
>
>
> OK. I can see how that works, assuming that the value would be
> \"log[$week_no][classroom]\" as well.
>
> What would the mysql_fetch_array look like?
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