Have you got an '@' in front of the mysql_query() to supress errors ?
Evan Morris wrote:
I have successfully managed to connect to the mysql database, using the
mysql_connect('localhost','php','*******') || die ("Unable to connect to
$db = mysql_select_db("DB_NAME") || die ("Unable to select requested
I then issue the following command:
$result = mysql_query("SELECT * FROM SOME_TABLE") || die(mysql_error());
This does not result in any error.
Now, of course, I want to work with the data returned, so I go:
if (mysql_num_rows($result) > 0)
// do some stuff
// do some other stuff
However, this gives me: "Supplied argument is not a valid MySQL result
If I go: echo "$result", I get '1', so I know $result actually has some
What am I doing wrong? Basically, I want to do the simplest thing: get data
out of a table and step through the results, displaying them one by one. Why
is this hard?
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