Your if statement will only be TRUE if $id is set to FALSE, NULL or zero (0)--I think you're looking for if the variable is set. That would be: if (isset($id))
-- Jason Godesky [EMAIL PROTECTED] http://www.tribaldawn.com/jason/
I'm a beginner of PHP. While trying the code from a tutorial, I encountered the following problem.
The variable $id can not be transfered to my server. You can find the code at the end of this email. When I visit http://mydomain.com/test.php?id=1 it always shows the list of the database instead of a perticular record.
I appreciate your kind helps!
Zhan Xu EECS Department Case Western Reserve University
-- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
