How about "if (isset($_GET["id"]))" ?
[EMAIL PROTECTED] wrote:
Thank you very much for your quick reply. I tried the if (isset($id)) but it doesn't work. Any thoughts?
By the way, I'm using Php4.3.3 and MySQL4.0.15a. The tutorial I'm reading is about Php3. Will this be the problem?
Zhan Xu EECS Department Case Western Reserve University
----- Original Message ----- From: Jason Godesky <[EMAIL PROTECTED]> Date: Monday, October 6, 2003 5:52 am Subject: Re: [PHP-DB] SoS
Your if statement will only be TRUE if $id is set to FALSE, NULL or zero (0)--I think you're looking for if the variable is set. That would be: if (isset($id))
-- Jason Godesky [EMAIL PROTECTED] http://www.tribaldawn.com/jason/
I'm a beginner of PHP. While trying the code from a tutorial, I encountered the following problem.
The variable $id can not be transfered to my server. You can find the code at the end of this email. When I visit http://mydomain.com/test.php?id=1 it always shows the list of the database instead of a perticular record.
I appreciate your kind helps!
Case Western Reserve University
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