elk dolk wrote:
thanks to Chris and Dimiter,
I think I am close but still the problem is not solved, when I add

echo "<img src='/album/img/".$row["photoFileName"]."' /> to the code as it was sugested by Dimiter there is parse Error :

PHP Parse error: syntax error, unexpected $end in 
C:\Inetpub\wwwroot\album\show.php on line 44

line 44 is end of the code just after </html>

what does it mean?
probably you don't have a semi colon at the end of your echo line....
nor is there and end double quote.

I am storing just the name of photos in the database and the photos are in /img folder ,and there is no permissions issue. My testing server
is IIS And the path would be something like this : Inetpub\wwwroot\album\img
as I am running out of time! could someone complete this code just with one echo and img src so that I can retrive my photos ?

MySQL columns : photoID=seq number
               photoFileName=name of my photo like 3sw.jpg
               description=short description


$link = mysql_connect('localhost', 'root', 'pw');
if (!$link) {
             die('Not connected : ' . mysql_error());
              echo 'connected!';

$db_selected = mysql_select_db('album', $link);
if (!$db_selected) {
                    die ('Can\'t use foo : ' . mysql_error());

$query = "SELECT * FROM photo";

while ($row = mysql_fetch_array($result)) { echo "<img src='/album/img/".$row["photoFileName"]."' /> }



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