At 22:30 21/3/2001, Björn Schotte wrote:
>I recently had a discussion with Alexander Aulbach
>(submitter of bug reports with unset() and the
>inconsistencies with unset($foo) and unset($bar["bla"])
>(the latter works, the former not))
Huh? Both work...?
> and we agreed
>that there definitively would be need of a funtion
>Sometimes we would like to know if $foo is a references
>variable or not (e.g. to ship around the unset() bug
>What do you think?
This has been discussed before (as far as I recall). The engine may
convert certain variables to be references on the fly, without the user
requesting it. So, is_reference() won't mean much to end users.
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