> >inconsistencies with unset($foo) and unset($bar["bla"])
> >(the latter works, the former not))
> Huh? Both work...?
Here it is in detail:
> This has been discussed before (as far as I recall). The engine may
> convert certain variables to be references on the fly, without the user
> requesting it. So, is_reference() won't mean much to end users.
In case of the former bug reports, I think it would
Björn Schotte [EMAIL PROTECTED]
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