Thanks a lot for all the patient replies. All the suggestions led me in a positive direction. Finally, instead of using the header() in my main PHP file (with HTML tags), I have used it in a secondary file and called it using a tag<img src="imgtest.php">. It is working fine. But, the image I need to display is also dynamic and needs a user input. So, is there any way in which I can transfer a particular variable (the user input) from my main php file (say A.php) to my secondary file containing the header () (say B.php)


Nathan Nobbe wrote:

On Mon, Mar 9, 2009 at 7:32 AM, Sashikanth Gurram <sashi...@vt.edu <mailto:sashi...@vt.edu>> wrote:


    Yes, the problem was solved, but It did not work fine when I used
    the same code in my larger file. Now it makes sense.

right, just track down where you started sending the output, and remember if youre going to use header() calls in your scripts, that all of them must come before sending any of the standard content.
    Let me just repeat what you have said just to make sure that I did
    not misread you.
    So you say that the solution to this problem is to create another
    php file with the image fetching header and just write an img tag
     <img src="myimagescript.php?id=1234" /> in my original php file
    (with the html tags).

what i explained in my first response is that youre mixing 2 different approaches, and it was unclear what you were going for exactly. if you want to have an image included in a page of html, then theres no need for the header() call (refer to my first response for the remaining details). there are however legitimate use cases for the use of header() & the aforementioned image methods, i think between mine and some of the other posts on this thread, its explained clearly.
    This is what I have understood.
    Regarding the point you have mentioned ( If you set the content
    type using header() to "image/jpeg", do not use HTML tags to
    display your image!),

    I definitely need the HTML tags, because this application works
    based on the user input. So unless there is not input through a
    html form, it wont work.

right, then just configure your webserver such that you can first access the image directly via an http url, then integrate these links into your dynamic pages as i explained in my first response.

good luck,


Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA

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