On Sep 25, 2009, at 3:12 PM, Geert Tapperwijn <g.tapperw...@gmail.com> wrote:

Can't you just use the eval <http://nl2.php.net/eval> function, and parse
the code from the include file in it?

.. or is there something I'm missing her

Because eval has risks if code gets injected into the code you mean to run.


Sent from my iPod

2009/9/25 Carl Furst <cfu...@intracommunities.org>

Jim Lucas wrote:

Ashley Sheridan wrote:

On Wed, 2009-09-23 at 07:36 -0700, Jim Lucas wrote:

Mert Oztekin wrote:

Output buffering will do it.

Also I am not sure but did you try retrieving content with fopen () ?

Something like

$file = 'invoicetable_bottom.php';


worth trying. Easier than output buffering

This would not work. fopen would open the file for read. What you
would be
reading is the actual source of the document. Not the data the script
output when ran.

The ob_* functions are the only way that I know of to do what you are

-----Original Message-----
From: Puiu Hrenciuc [mailto:hp...@xentra.ro]
Sent: Wednesday, September 23, 2009 1:36 PM
To: php-general@lists.php.net
Subject: [PHP] Re: How to take output from an include, and embed it
into a variable?


The simplest way (actually the single way I know :) ) would be to
capture the output using output buffering functions, something like

// start output buffering

// include the file that generates the HTML (or whatever content)
include "....";

// get output buffer content

// clean output buffer and stop buffering

// the content generated in the included file is now in $output
// use it as you consider fit


Rob Gould wrote:

I have an invoice table that is drawn on a number of pages, so I have
all the logic in an include-file like this:

include "invoicetable_bottom.php";

However, now I'm needing to take the output from that include file and pass it as an email. To do that, I need to somehow take the output
this include file and get it into a variable somehow. Is there a
way to do this?

Something like: $emailtcontent = include "invoicetable_bottom.php"?

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That's just crazy talk. If you use fopen on a web URL, then it will
always return the output the script generates. That's how http works!

Sorry, my bad. Ash is correct, the method that is suggested will work.
But you
will need to enable options in your php.ini that are not on by default for security reasons, plus as Ben points out, you will need to filter out the
that is generated to capture just the data output from your include.

Mind you that all of this also requires that the file that you are
including is
accessible via the web.  It could be in a folder that is not web

Sorry for the initial confusion!


Do you have php configured to compile files? Why not just backtick the php
-f command??


$cmd = *escapeshellcmd*("/full/path/to/php -f $file");
$email_output = `$cmd`;

# do something with $email_output


Seems easier than a whole http call.. can be risky if the $file variable can be set by user input (big no no), but other than that.. seeems the

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