> -----Original Message-----
> From: Ben Dunlap [mailto:bdun...@agentintellect.com] 
> Sent: Friday, October 02, 2009 2:58 PM
> To: php-general@lists.php.net; Daevid Vincent
> Subject: Re: [PHP] Whacky increment/assignment logic with 
> $foo++ vs ++$foo
> 
> > mind-blowing. What the heck /is/ supposed to happen when 
> you do this:
> >
> >    $a = 2;
> >    $a = $a++;
> >    echo $a;
> >
> > Seems like any way you slice it the output should be 3. I 
> guess what's
> 
> ... and, in fact, that /is/ how C behaves. The following code:
> 
>       int a = 2;
>       a = a++;
>       printf("a = [%d]\n", a);
> 
> Will output "a = [3]". At least on Ubuntu 9 using gcc 4.3.3.
> 
> So I retract my initial terse reply and apologize for misunderstanding
> your question.
> 
> Ben

EXACTLY! :)

God (or diety of your choice) bless you for "getting" what I'm saying and
proving that it's not "C" like either. That just adds credence to my/our
argument.


d


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