"Daevid Vincent" wrote:

>  
> 
>> -----Original Message-----
>> From: Ben Dunlap [mailto:bdun...@agentintellect.com]
>> Sent: Friday, October 02, 2009 2:58 PM
>> To: php-general@lists.php.net; Daevid Vincent
>> Subject: Re: [PHP] Whacky increment/assignment logic with
>> $foo++ vs ++$foo
>> 
>> > mind-blowing. What the heck /is/ supposed to happen when
>> you do this:
>> >
>> > $a = 2;
>> > $a = $a++;
>> > echo $a;
>> >
>> > Seems like any way you slice it the output should be 3. I
>> guess what's
>> 
>> ... and, in fact, that /is/ how C behaves. The following code:
>> 
>> int a = 2;
>> a = a++;
>> printf("a = [%d]\n", a);
>> 
>> Will output "a = [3]". At least on Ubuntu 9 using gcc 4.3.3.
>> 
>> So I retract my initial terse reply and apologize for misunderstanding
>> your question.
>> 
>> Ben
> 
> EXACTLY! :)
> 
> God (or diety of your choice) bless you for "getting" what I'm saying and
> proving that it's not "C" like either. That just adds credence to my/our
> argument.
> 
> 
> d

Well, Daevid,

I still do appreciate the difference between

        $a = 1;
        $b = $a++;
        // $b should be 1
and

        $a = $a++;
        $b = $a;
        // $b should be 2

unless PHP manages to exhibit some overlay problem  (read: bug) for $a in 
the 2nd case.

True?
joost.


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