> Date: Wed, 26 May 2010 09:19:26 -0400
> To: [email protected]; [email protected]
> From: [email protected]
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
>
> At 9:17 PM -0400 5/25/10, Alice Wei wrote:
> >No, the fields are populated in the first and second
> >form, form1 and form2. What I want to do is to get the selections from
> >both forms and pass them on to the third. Does this make sense? For some
> > reason, the text input and the semester drop down menu result can be
> >passed to process.php, but the results that I try to select from the
> >first and second does not. So, the form is not passing the results of
> >what I had from the radio button selections.
> >
> >To illustrate, the
> >second looks something like this:
>
> Alice:
>
> No offense, but "Looking" like something isn't going to cut it.
>
> I advise you to:
>
> 1. Show us the code. -- give us a url where your code is located.
>
> 2. Tell us what you *want* to do -- and don't show us with "it looks
> something like this" nonsense.
>
> 3. Get the simple stuff to work first before jumping into the harder stuff.
>
> If you are willing to do the above, then I'll help you with your problem.
>
> Please understand that forms are very simple with very simple rules
> to follow. Enhancing forms with javascript routines can become
> complicated very quickly. But if you can describe it, it can be done.
>
> Cheers,
>
> tedd
>
>
I thought I provided the whole code, but looks like it somehow got lost in the
thread.
Here is the main file I would like to use for my data entry:
Main:
<?php
// Make a MySQL Connection
mysql_connect("localhost", "xxx", "xxx") or die(mysql_error());
mysql_select_db("yyy") or die(mysql_error());
//The variables posted from the PHP form
$start = $_POST["start"];
?>
<ul>
<form action="" method="post">
<li>Select the type of your starting point of interest:<br/>
<div id="start_menu"><form
action="test_getrss.php" name="form1" method="post">
<span><input type="radio"
value="Apartment" name="start"
onclick="check(document.form1.start)"/> Apartment </span>
<span><input type="radio"
value="Grocery" name="start"
onclick="check(document.form1.start)"/> Grocery </span>
</form></div></li> </ul>
<form action="process.php" method="post">
<input type="hidden" name="form1" value="<?php echo
$start?>"/>
<input type="submit" value="Submit" name="submit"/>
<input type="reset" value="Reset" name="reset"/>
</form>
</body>
</html>
This is the script that I use to construct the drop down menu in test_getrss.php
<?php
//get the q parameter from URL
// Make a MySQL Connection
mysql_connect("localhost", "xxx", "xxx") or die(mysql_error());
mysql_select_db("xxxe") or die(mysql_error());
$q=$_GET["q"];
$query="SELECT name FROM start_from WHERE type='" . $q . "'";
//find out which feed was selected
$result = mysql_query ($query);
echo "<select name='start_location'>";
// printing the list box select command
while($nt=mysql_fetch_array($result)){//Array or records stored in $nt
echo "<option value=$nt[0]>$nt[0]</option>";
/* Option values are added by looping through the array */
}
echo "</select>";// Closing of list box
?>
See, I am trying to get the users pick something from the <select
name="start_location"> and have the info in there to pass on to process.php
<?php
//get the q parameter from URL
// Make a MySQL Connection
mysql_connect("localhost", "xxx", "xxx") or die(mysql_error());
mysql_select_db("yyy") or die(mysql_error());
$form1 = $_POST['form1'];
echo "Start Location " . $form1 . "<br />";
?>
Therefore, the radio button info. does not need to be recorded. This is not the
only field I need to pass to process.php, which the data would be used to enter
into a database. I am leaving what is not working in my code. I hope this helps
in understanding what my problem may be.
Thanks for your help.
Alice
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