If you needed the double-quotes in the Xpath expression when the constant is used , then you probably need them in the variable version.

$v = $row->xpath('//membernumber[. = "'.$MemberId.'"]');

That should put the double-quotes in for you...

On 15/09/10 09:33, Sridhar Pandurangiah wrote:

-------- Original Message --------
Subject: Re: Xpath arguments in variable
From: php-gene...@garydjones.name (Gary)
Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST)

Whats wrong with
$v = $row->xpath('//membernumber[. = ' . $MemberId . ']');

Am I not understanding what you are trying to ask?


I tried this but doesn't work. I guess the above statement is
concatenating the entire string and the substitution isn't happening

What I am trying to do is as follows
$MemberId = 'A192';
$v = $row->xpath('//membernumber[. = ' . $MemberId . ']');

The $MemberId should be substituted with A192 and then the xpath query
should be executed. The result should be that I locate the membernumber
XML element that has the value A912.

Best regards


Sridhar Pandurangiah wrote:
now I need to pass this value to XPath within a string variable say

$v = $row->xpath('//membernumber[. = $MemberId]');

But this doesnt work due to the quotes. What I intend PHP to do is to
substitute the value for $MemberId and then execute the XPath query. I
have grappled with it for a few days before posting this.

Whats wrong with $v = $row->xpath('//membernumber[. = ' . $MemberId .

Am I not understanding what you are trying to ask?

Peter Ford, Developer                 phone: 01580 893333 fax: 01580 893399
Justcroft International Ltd.                              www.justcroft.com
Justcroft House, High Street, Staplehurst, Kent   TN12 0AH   United Kingdom
Registered in England and Wales: 2297906
Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17 1XS

PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to