What about something like this:
$pos = (strpos(' ', $string, 76))?strpos(' ',$string, 76):strlen($string);
Thanks,
Ash
http://www.ashleysheridan.co.uk
----- Reply message -----
From: "Ron Piggott" <[email protected]>
Date: Sun, Nov 14, 2010 20:48
Subject: [PHP] Re: String manipulation
To: <[email protected]>
How would I write an IF statement that looks for the first space space (“ “)
left of the 76th character in a string or <br>, which ever comes first --- OR
the end of the string (IE the string is less than 76 characters long? I
specifically want is it’s character position in the string. Ron
The Verse of the Day
“Encouragement from God’s Word”
http://www.TheVerseOfTheDay.info
