What about something like this:

$pos = (strpos(' ', $string, 76))?strpos(' ',$string, 76):strlen($string);


----- Reply message -----
From: "Ron Piggott" <ron.pigg...@actsministries.org>
Date: Sun, Nov 14, 2010 20:48
Subject: [PHP] Re: String manipulation
To: <php-general@lists.php.net>

How would I write an IF statement that looks for the first space space (“ “) 
left of the 76th character in a string or <br>, which ever comes first --- OR 
the end of the string (IE the string is less than 76 characters long? I 
specifically want is it’s character position in the string.  Ron

The Verse of the Day
“Encouragement from God’s Word”

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