I am receiving this error: Warning: strpos() [function.strpos]: Offset not contained in string
I have never seen it before, what do I do? I made one change to it though, you didn’t have <br> in it before so I changed the syntax to: $pos = (strpos(' ', $activity_description_result, 76))?strpos('<br>',$activity_description_result, 76):strlen($activity_description_result); Ron The Verse of the Day “Encouragement from God’s Word” http://www.TheVerseOfTheDay.info From: a...@ashleysheridan.co.uk Sent: Sunday, November 14, 2010 4:58 PM To: Ron Piggott ; php-general@lists.php.net Subject: Re: [PHP] Re: String manipulation What about something like this: $pos = (strpos(' ', $string, 76))?strpos(' ',$string, 76):strlen($string); Thanks, Ash http://www.ashleysheridan.co.uk ----- Reply message ----- From: "Ron Piggott" <ron.pigg...@actsministries.org> Date: Sun, Nov 14, 2010 20:48 Subject: [PHP] Re: String manipulation To: <php-general@lists.php.net> How would I write an IF statement that looks for the first space space (“ “) left of the 76th character in a string or <br>, which ever comes first --- OR the end of the string (IE the string is less than 76 characters long? I specifically want is it’s character position in the string. Ron The Verse of the Day “Encouragement from God’s Word” http://www.TheVerseOfTheDay.info